Math, asked by abdulrasheedmanar, 9 months ago

The father’s age is six times his son’s age. Four years hence, the age of the father will be four times his son’s age. The present ages of the son and the father are, respectively (a) 4 and 24 (b) 5 and 30 (c) 6 and 36 (d) 3 and 24 Answer Answer: c

Answers

Answered by saavya5
2

Answer:

4 and 24

Step-by-step explanation:

son age be x

then father is 6x

4 y later

son is x+4

father is 6x+4

ATP

6x+4 = 4(x+4)

6x+4 = 4x+16

6x - 4x = 16- 4

2x = 8

x= 8/2 = 4

hence son 4years

father 6x= 24 years

HOPE IT HELPS

Answered by saksham200663
3

Answer:

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