Question

The father’s age is six times his son’s age. Four years hence, the age of the father will be four times his son’s age. The present ages, in years, of the son and the father are, respectively





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Answer 1

Step-by-step explanation:

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10th

Maths

Pair of Linear Equations in Two Variables

Reducing a Pair of Equations to Linear Form

The father's age is six tim...

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The father's age is six times his son's age. Four years hence, the age of the father will be four times his son's age. The present ages, in years, of the son and the father are respectively,

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ANSWER

Let the present age of father's be x years and present age of son's be y years.

According to the problem

x=6y

After 4 years

x+4=4(y+4)

Hence we get two equations

x=6y ......... (1)

x+4=4(y+4) ..... (2)

Simplifying eq (2)

x+4=4y+16

x−4y=12

Put x=6y in eq (2), we get

6y−4y=12

2y=12

y=6 years

and x=6y=36 years

Present age of son =6 years

and present age of father =36 years

Answer 2

Step-by-step explanation:

Let's father's age is x years and

son's age is y years

ATQ,

4(x+4)

6x+4=4(x+4)

6x+4=4x+16

2x=12

x=6

so,

6x

=6×6

=36

father's age is 36

hope it helped you