Math, asked by Swappy07, 5 months ago

The federal match company has 40 female and 60 male
employees of 2 employees are seated at random then how
many ways selections are possible !
a) Both will be male
b) There will be one of each gender​

Answers

Answered by rosyjoy444
3

Answer:

B

HOPE IT WAS HELPFUL TO YOU

Answered by arshikhan8123
0

Concept:

Formula for combination is given by:

n C r = n! / r!(n - r)!

Given:

We are given that there are 60 males and 40 females.

Find:

We need to find the number of ways of selection in which both the members are male and then that there will be one of each gender​.

Solution:

a) We have that:

n = 60

r = 2

60 C 2 = 60! / 2! ( 60 - 2 )!

= 1770

b) We have that:

n₁ = 60 and n₂ = 40

r₁ = 1 and r₂ = 1

Ways = 60 C 1 + 40 C 1

= 60! / 1! (60-1)!  + 40! / 1!(40-1)!

= 60 + 40

= 100 ways.

Therefore, we get that the number of ways for selecting both the male candidates are 1770 and the ways for selection that there will be one of each gender​ is 100.

#SPJ2

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