Question

The fermi level for potassium is 2.1 eV. Calculate the velocity of the electrons at the fermi level.

Answer 1

Answer:

The Fermi level for potassium is 2.1eV. Calculate the velocity of the electron at the Fermi level. Solution:- We have the formula, = 1 2 2 Therefore, = 2 1 2 = 2 × 2.1 × 1.602 × 10−19 / 9.11 × 10−31 1 2 = 8.6 × 10 5 /.

Answer 2

Concept:

The highest energy state that an electron can occupy at absolutely the zero temperature is thought because the Fermi Level.

Given:

We are given the Fermi level for potassium is $2.1eV.$

Find:

We have to seek out the rate of the electrons at the fermi level.

Solution:

We will find the speed using the formula $E_{F}=\frac{1}{2}mv_{F}^{2}$

Here, $E_{F}=2.1eV \times 1.602 \times 10^{-19} J/eV$ and $m=9.11\times 10^{-31}Kg$.

The $1.602\times 10^{-19}$ is that the columb of a unit charge in Joule per electro volt.

Now, we'll substitute these values within the formula, we get

$\begin{aligned}v_{F}&=\sqrt{\frac{2E_{F}}{m}}\\ &=\sqrt{\frac{2\times 2.1eV \times 1.602\times 10^{-19}J/eV}{9.11\times 10^{-31}Kg}}\end$

Further, we'll simplify the above expression, we get

$v_{F}=8.6\times 10^{5}m/s$

Hence,  the speed of the electrons at the fermi level is $8.6\times 10^{5} m/s$.

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