Question

the field.
A2. The sum of three consecutive multiples of 8
is equal to eight times the sum of the first two
consecutive multiples of 6. Find each of the three
multiples of 8



plz answer fast if possible and plz also slove on a paper ​

Answer 1

GIVEN:

Sum of three consecutive multiples of 8 is equal to eight times the sum of the first two consecutive multiples of 6.

TO FIND:

The three multiples of 8.

SOLUTION:

Let,

The three multiples of 8 be x, x + 8 and x + 16

The first two multiples of 6 are 6 and 12

According to the question,

x + x + 8 + x + 16 = 8 ( 6 + 12)

3x + 24 = 144

3x = 144 - 24

==> 3x = 120

==> x = 120/3

==> x = 40

First multiple = 40

Other multiples:

x + 8 = 40 + 8 = 48

x + 16 = 40 + 16 = 56

Therefore, the consecutive multiples of 8 are 40, 48 and 56

Answer 2

Given:

• Sum of three consecutive multiples of 8 = 8 × sum of first 2 consecutive multiples of 6

To find:

• Other three multiples of 8

Solution:

Let first multiple be x

Then, other 2 multiples be x + 8 , x + 16

The 1st two multiples of 6 are : 6 , 12

According to the question:

→ x + (x + 8) + (x + 16) = 8(6 + 12)

→ 3x + 24 = 8(18)

→ 3x = 144 - 24

→ 3x = 120

→ x = 120/3

→ x = 40

Finding : Other three multiples

→ x + 8 = 40 + 8 = 48

→ x + 16 = 40 + 16 = 56

→ x + 24 = 40 + 24 = 64

Hence , Other three multiples are 48 , 56 , 64