Question

The field B = −2ax + 3ay + 4 az mT is present in free space. Find the vector force exerted on a straight
wire carrying 12 A in the aAB direction, given A(1,1,1) and B(3,5,6).

Answer 1

Answer:

Given :-

Mass of the body = 5 kg

Velocity of the body = 2 m/s

To Find :-

The linear momentum of the body.

Analysis :-

Here we are given with the mass and velocity of the body moving.

In order to find the linear momentum substitute the given values from the question such that linear momentum is equal to mass multiplied by the velocity of the body moving.

Solution :-

We know that,

p = Momentum

m = Mass

v = Velocity

Using the formula

$\underline{\boxed{\sf Momentum=Mass \times Velocity}}$

Given that,

Mass (m) = 5 kg

Velocity (v) = 2 m/s

Substituting their values,

⇒ p = mv

⇒ p = 5 × 2

⇒ p = 10 kg m/s

Therefore, the linear momentum of the body is 10 kg m/s.