THE FIELD IN THE FORM OF A PARALLELOGRAM HAS ONE OF ITS DIAGONALS 42 M LONG AND THE PERPENDICULAR DISTANCE OF THIS DIAGONAL FROM EITHER OF THE OUTLYING VERTICES IS 10.8 M(SEE FIG. 20.16). FIND THE AREA OF THE FIELD.
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In the Field ABCD,
Area of the field=Area of ∆DAC+Area of ∆ BCA
Area of the field= ½×AC×LD+½×AC×MB
Area of the field= ½×AC(LD+MB)
Area of the field= ½×42(10.8+10.8)
Area of the field= ½×42×21.6
Area of the field= 21×21.6=453.6
.
. . So, the area of the field is 453.6m².
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