Question

The field N value in a deposit of fully submerged fine sand was 40 at a depth of 6 m.

The average unit weight of soil is 18 kN/m3

. Calculate the corrected N value as per

IS:2131-1981​

Answer 1

Answer:

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Answer 2

The corrected N value is 25.2 according to IS:2131-1981.

To find,

The corrected N value as per IS:2131-1981​.

Given,

The field N value in a deposit of fully submerged fine sand was 40 at a depth of 6 m.

Solution,

The corrected N value can be calculated using the formula:

Nc = Nq * (C1 * C2 * C3)

where,

Nq = measured N value = 40

C1 = correction factor for overburden pressure = 1

C2 = correction factor for the shape of the penetrometer tip = 1

C3 = correction factor for the type of soil = 0.65 (for fine sand)

Therefore,

Nc = 40 * (1 * 1 * 0.65) = 26

The corrected N value is 26.

The corrected N value, Nc, can be calculated using the following formula:

Nc = Nq * C1 * C2 * C3

where Nq is the measured N value, and C1, C2, and C3 are correction factors based on the type of soil and testing conditions.

For fully submerged fine sand, the correction factors are:

C1 = 1.0 (no correction for overburden pressure)

C2 = 1.0 (no correction for soil density)

C3 = 0.63 (correction factor for fully submerged sand)

Plugging in the values, we get:

Nc = 40 * 1.0 * 1.0 * 0.63

Nc = 25.2

Therefore, the corrected N value is 25.2 according to IS:2131-1981.

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