Question

*The height and diameter of a conical flask is 15 cm and 14 cm respectively. Find the amount of water it can contain.* 1️⃣ 364.16 cm³ 2️⃣ 770 cm³ 3️⃣ 518.16 cm³ 4️⃣ 154 cm³​

Answer 1

Given :

• The height and diameter of a conical flask is 15 cm and 14 cm respectively .

To Find :

• Amount of water it can contain .

Solution :

$\longmapsto\tt{Height\:of\:flask(h)=15\:cm}$

$\longmapsto\tt{Radius\:of\:flask(r)=\dfrac{14}{2}=7\:cm}$

Using Formula :

$\longmapsto\tt\boxed{Volume\:of\:Cone=\dfrac{1}{3}\pi{{r}^{2}h}}$

Putting Values :

$\longmapsto\tt{\dfrac{1}{\cancel{3}}}\times\dfrac{22}{{\cancel{7}}}\times{{\cancel{7}}}\times{7}\times{{\cancel{15}}}$

$\longmapsto\tt{22\times{7}\times{5}}$

$\longmapsto\tt\bf{770\:{cm}^{3}}$

So , The amount of water it can contain is 770 cm³ .

Option 2) 770 cm³ is Correct .

__________________

• C.S.A of Cone = πrl
• T.S.A of Cone = πr(l+r)
• Volume of Cone = ⅓πr²h

Here :

• r = radius of cone
• h = height of cone
• l = slant height of cone
• π = 22/7 or 3.14

__________________

Answer 2

2️⃣ 770 cm³ is the correct answer.

Step-by-step explanation:

Given,

★ The height of the conical flask is h = 15 cm

★ The diameter of the colical flask d = 14 cm

So, radius of the conical flask is r = 14/2 = 7 cm

To Find :

→ The amount of water it can contain .

Solution :

☞ Amount of water = Volume of the flask

We know that,

$\green{ \bf{Volume\:of\:Cone \: \: V \: \: =\dfrac{1}{3}\pi{{r}^{3}h}}} \\ \\ \bf \implies \: V = \frac{1}{3} \times \frac{22}{7} \times {7}^{3} \times 15 \\ = \frac{1}{3} \times \frac{22}{7} \times 343 \times 15 \\ = 770 \: {cm}^{3}$