Question

the fifth term of an AP is52 and its twelfth term is 24. find AP​

Answer 1

Answer:

Step-by-step explanation:

Given that-

a₅ = 52

a₁₂ = 24

To find-

the AP

Solution-

we know that- aₙ = a + (n-1) x d

∴ a₅ = a + 4d----1

and a₁₂ = a + 11d----2

subtracting equation 1 from equation 2,

a₁₂ - a₅ = (a + 11d) - (a + 4d)

24 - 52 = a + 11d - a - 4d = 7d

-28 = 7d

7d = -28

d = -28 / 7

d = -4

in equation 1

a + 4d = 52

putting d = -4

a + -16 = 52

a= 52 + 16

a= 68

we know ,

AP -

a , a+d , a+2d ...

∴ AP = 68 , 68 -4 , 68 -8 ...

AP = 68 , 64 , 60 ...

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