Question

The Fig. 17 24 shows a circle with centre at O and AOB=90°. If the radius of the circle is 40cm, calculate the area of the shaded portion of the circle.
No spam correct answer = Brainlist ​

Answer 1

Step-by-step explanation:

see the attached document for the steps

Answer 2

Answer:

hey here is your solution in above pics

pls mark it as brainliest

Step-by-step explanation:

$so \: basically \: here \: shaded \: portion \: represents \: area \: covered \: by \: segment \: AB \\ so \: we \: had \: to \: find \: here \: basically \: area \: of \: segment \: AB \\ so \: here \\ radius \: (r) = 40 \: cm \\ θ = 90 \\ \pi = 3.14$

$so \: hence \: using \: \\ area \: of \: segment \: AB = r {}^{2} \times (\pi.θ/360 - \sin \: θ/2) \\ = (40) {}^{2} \times (3.14 \times 90/360 - sin \: 90/2) \\ = 1600 \times (3.14/4 - 1 \times 1/2) \\ since \: sin \: 90 = 1 \\ = 1600(3.14/4 - 1/2) \\ = 1600 \times (3.14/4 - 1/2 \times 2/2) \\ = 1600(3.14 /4 - 2/4) \\ = 1600(3.14 - 2/4) \\ = 1600 \times 1.14 \times 4 \\ = 1.14 \times 400 \\ = 456 \: cm {}^{2}$

$hence \: area \: of \: shaded \: region \: is \: 456 \: cm {}^{2}$