Question

the fig shows the position time graph of a particle moving on a straight line path. what is the magnitude of average velocity of the particle over 10 seconds

Answer 1

Answer:

1)2m/s

Explanation:

$avg.velocity = \frac{x2 - x1}{t2 - t1}$

where, x1= position of the particle at time t1

x2=position of the particle at time t2

here, t1=0s

t2=10s

x1= 60

x2=40

therefore,

$avg.velocity = \frac{40 - 60}{10 - 0} \\ = \frac{ - 20}{10} \\ = - 2$

magnitude= |-2|=2m/s

Answer 2

The fig. shows the position time graph of a particle moving on a straight line path. What is the magnitude of average speed of the particle over 10 seconds ?