Question

the figure AB = QR, AC = PQ, BC = PR ;

Also ∠A = 50°, ∠B = 60°

a) ∠Q = ………….

b) ∠P = …………..​

Answer 1

Answer:

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Step-by-step explanation:

Given :-)

AB = QR, AC = PQ, BC = PR

By SSS congruence rule

∆ABC ≈ ∆PQR

so,

∠Q = 50°

∠P = 60°

By CPCT, all the angles of both the triangle will be same as they are congruent

CPCT - ( Corresponding Parts of Congruent Triangle)

Answer 2

Given:$\[AB = QR,AC = PQ,BC = PR\]$,$\[\angle A = 50^\circ ,{\rm{ }}\angle B = 60^\circ \]$

Find: $\[\angle Q,\angle P\]$.

Solution:

Know that,

$\[AB = QR,AC = PQ,BC = PR\]$

Therefore, by SSS congruency

$\[\Delta ABC \cong \Delta PQR\]$

Therefore,By CPCT, all the angles of both the triangle will be same as they are congruent.

Hence,

$\[\begin{array}{l}\angle Q = {50^ \circ }\\\angle P = {60^ \circ }\end{array}\]$