The figure below is formed using 2 identical squares of side 10 cm and 2 equilateral triangles. Find the perimeter of the figure.(in cm)
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Hey bro!!
Here is your solution.....
We Have To Find Perimeter Of The Given Figure..
Perimeter means the total measure of boundary line of any geometrical figure.
Perimeter of figure = AF + FM + ME + EN + ND + DC + CB + BA.
Here ◻ABEF and ◻BEDC are square having measure of sides 10 cm.
So, In ◻ABEF
AB = BE = EF = FA = 10cm. .... (1)
In ◻ BEDC
BE = ED = DC = CB = 10cm. ..….(2)
As given that triangles ∆ FME and ∆END are equilateral triangles.
In ∆FME, EF = 10cm. .... { from (1)}
EF = FM = ME = 10cm
In ∆END, ED = 10cm. .....{from (2)}
ED = DN = NE = 10cm.
Now, Perimeter of figure = AF + FM + ME + EN + ND + DC + CB + BA.
= 10 + 10 + 10 + 10 + 10 + 10 + 10 + 10
= 80 cm
HOPE IT HELPS YOU.....
THANKS
^-^
Here is your solution.....
We Have To Find Perimeter Of The Given Figure..
Perimeter means the total measure of boundary line of any geometrical figure.
Perimeter of figure = AF + FM + ME + EN + ND + DC + CB + BA.
Here ◻ABEF and ◻BEDC are square having measure of sides 10 cm.
So, In ◻ABEF
AB = BE = EF = FA = 10cm. .... (1)
In ◻ BEDC
BE = ED = DC = CB = 10cm. ..….(2)
As given that triangles ∆ FME and ∆END are equilateral triangles.
In ∆FME, EF = 10cm. .... { from (1)}
EF = FM = ME = 10cm
In ∆END, ED = 10cm. .....{from (2)}
ED = DN = NE = 10cm.
Now, Perimeter of figure = AF + FM + ME + EN + ND + DC + CB + BA.
= 10 + 10 + 10 + 10 + 10 + 10 + 10 + 10
= 80 cm
HOPE IT HELPS YOU.....
THANKS
^-^
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KunalTheGreat:
correct! tqsm
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