Question

The figure below is made up of 4 semicircles, with
diameter 20 m, 18 m, 14 m, and 10 m respectively
​

Answer 1

Answer:

so what we have to do in this

Answer 2

Answer:

553. 14 m²

Step-by-step explanation:

Area of outer most circle:

$\frac{\pi {r}^{2} }{2} \\ = \frac{\pi {20}^{2} }{2}$

$\pi200 {m}^{2}$

Area of outer shaded region:

$\pi200 - \frac{\pi {12}^{2} }{2}$

$\pi200 - \pi72 \\ = \pi128 {m}^{2}$

Area of inner shaded region :

$\frac{\pi {14}^{2} }{2} - \frac{\pi {10}^{2} }{2}$

=

$\frac{\pi96}{2} \\ = \pi48 {m}^{2}$

Area of total shaded region:

=pi ( 48 + 128) m²

=22/7 × 176m²

= 553.14..m²