The figure (i) given below shows the cross-section of the concrete structure with the measurements as given. Calculate the area of cross-section.
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Answer:
51.59cm²
Step-by-step explanation:
Area of isosceles triangle=√3/4×6×6
=9√3cm²
by Pythagoras we get,(GD)²=(GB)²+(BD)²
(5)²=(3)²+BD²
25=9+BD²
BD²=25-9
BD²=16
BD=4
=4cm
Area of rectangle=l×b
l=6cm
b=4cm
6×4
=24cm²
Area of right angle triangle=½×3×4
=6×2
=12cm²
Area of enclosed figure=9√3+24+12
=15.588+24+12
=15.588+36
=51.588
=51.59cm²
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