Math, asked by swapnilbanerjee2007, 1 month ago

The figure (i) given below shows the cross-section of the concrete structure with the measurements as given. Calculate the area of cross-section.

No useless answers else your answer will be reported.​

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Answers

Answered by garimagup2006
0

Answer:

51.59cm²

Step-by-step explanation:

Area of isosceles triangle=√3/4×6×6

=9√3cm²

by Pythagoras we get,(GD)²=(GB)²+(BD)²

(5)²=(3)²+BD²

25=9+BD²

BD²=25-9

BD²=16

BD=4

=4cm

Area of rectangle=l×b

l=6cm

b=4cm

6×4

=24cm²

Area of right angle triangle=½×3×4

=6×2

=12cm²

Area of enclosed figure=9√3+24+12

=15.588+24+12

=15.588+36

=51.588

=51.59cm²

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