Question

the figure obtained by joining the mid point of the side of a rhombus take in order is​

Answer 1

Step-by-step explanation:

Your answer is :-

\begin{gathered}{a}^{2} - {(2a + 3b)}^{2} \\ \\ = (a + 2a + 3b)(a - 2a - 3b) \\ \\ = (3a + 3b)( - a - 3b)\end{gathered}

a

2

−(2a+3b)

2

=(a+2a+3b)(a−2a−3b)

=(3a+3b)(−a−3b)

Answer 2

Step-by-step explanation:

Your answer is :-

\begin{gathered}{a}^{2} - {(2a + 3b)}^{2} \\ \\ = (a + 2a + 3b)(a - 2a - 3b) \\ \\ = (3a + 3b)( - a - 3b)\end{gathered}

a

2

−(2a+3b)

2

=(a+2a+3b)(a−2a−3b)

=(3a+3b)(−a−3b)

Answer 3

Step-by-step explanation:

Your answer is :-

\begin{gathered}{a}^{2} - {(2a + 3b)}^{2} \\ \\ = (a + 2a + 3b)(a - 2a - 3b) \\ \\ = (3a + 3b)( - a - 3b)\end{gathered}

a

2

−(2a+3b)

2

=(a+2a+3b)(a−2a−3b)

=(3a+3b)(−a−3b)