the figure shows a circle of radius 14 cm with one quadrant removed t THE sides of square.FIND
(1) the perimeter of unshaded region
(2) the area of unshaded region ouching
(3) the rea of shaded region
Answers
Answer:
Solution:
(i) Perimeter of the unshaded region = perimeter of square - circumference of circle + perimeter of 2 sides
= 4×28 - 2 π ×14+2(14) [2r=side of square]
= 112 - 2(22/7)× 14 + 28
= 112 -88 +28
= 52 cm
(ii) The Area of unshaded region = Area of circle - Area of quadrant
= π (14)² - 1/4 π(14)²
= 22/7 × 14 × 14 - 1/4 × 22/7 × 14 × 14
= 616 - 154
= 642 cm²
iii) The Area of Shaded region = Area of Square - Area of unshaded region
= (28)² - 642
= 784 - 642
= 142 cm²
Answer
Hope this helped you....