the figure shows a quadrilateral ABCD where angle ABC=Angle BCD=90 degree given that AB=4m and DA=DC=7m Find Angle ADC
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Answered by
17
Answer:
64.62°
Step-by-step explanation:
Draw parallel of BC from A which cut DC name the point
now AB=EC
So DE=3 m (as AB=EC=4)
and AD=7 m
So cos(ADC)=3/7
so angle ADC=64.62°
Answered by
2
Answer:
64.60
Step-by-step explanation:
See the attachment
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