Question

The figure shows a rectangle ABCD. Point E lies on AB such that ADE = 51 degrees and DCE = 68 degrees. Find AED.Click to enlarge

AED = 38 degree
AED = 39 degree
AED = 40 degree
AED = 41 degree

Answer 1

Answer:

you add them you will get the answer

Answer 2

Given :- The figure shows a rectangle ABCD. Point E lies on AB such that ADE = 51 degrees and DCE = 68 degrees. Find AED.Click to enlarge

AED = 38 degree

AED = 39 degree

AED = 40 degree

AED = 41 degree

Answer :-

we know that,

• Each angle of a rectangle is equal to 90° .

so, in ∆DAE, we have,

→ ∠ADE = 51° (given.)

→ ∠DAE = 90° (angle of rectangle.)

then,

→ ∠ADE + ∠DAE + ∠AED = 180° (By angle sum property.)

→ 51° + 90° + ∠AED = 180°

→ 141° + ∠AED = 180°

→ ∠AED = 180° - 141°

→ ∠AED = 39° (B) (Ans.)

Learn more :-

In ABC, AD is angle bisector,

angle BAC = 111 and AB+BD=AC find the value of angle ACB=?

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