Question

The figure shows curve Of y=-x^2-x+20. The curve cuts the x axis at two points A and B. And y axis at point c find coordinates of A B AND C. The point D (3,4) lies kn the curve .find value of h

Answer 1

Answer:

This will help

f2a804f3843f096ebe5570123e955818.docx

Answer 2

Given:

y=-x² -x + 20

point D (3,4)

Find value of h = ?

$\text { So, when } x=0$

$y=-(0)^{2}-0+20\\=20$

$\text { the coordinate of } C \text { is }(0,20)$

$\text { when } y=0=-x^{2}-x+20$

-x² -x + 20=0

x=-5 or x=4

So the coordinate of A is (-5 , 0)

So the coordinate of B is (4 , 0)

when put x= 3

y= -x² -x + 20

y= -(3)² - 3 +20

y= -9 -3 +20

y=20-12

y=8

the point D (3,4) lies on the curve is equal to (3 , 8)

so the value of h is 8

Hence the value of h is 8