Question

the figure shows the accelaration versus time graph the particle starts from rest at t=0 Find the approximate velocity at t=1 sec

Answer 1

ProvidEd that:

• Initial velocity = 0 m/s

• Time = 1 second

• Acceleration at t as 1 s = 1.6 m/s²

• Final velocity = !???

Solution:

• Final velocity = 1.6 m/s

Using concept:

• First equation of motion

Using formula:

• ${\small{\underline{\boxed{\pmb{\sf{v \: = u \: + at}}}}}}$

Where, a denotes acceleration, u denotes initial velocity, v denotes final velocity and t denotes time taken.

Required solution:

${\sf{:\implies v \: = u \: + at}}$

${\sf{:\implies v \: = 0 + 1.6(1)}}$

${\sf{:\implies v \: = 0 + 1.6}}$

${\sf{:\implies v \: = 1.6 \: ms^{-1}}}$

${\sf{:\implies Final \: velocity \: = 1.6 \: ms^{-1}}}$

Therefore, final velocity is 1.6 metre per second. Henceforth, option (B) is correct!