Question

The figure shows two circle with same Centre the radius of larger circle is 10cm and the radius of smaller circle is 4 cm. Find the area of larger circle.​

Answer 1

here I attached the file refer it

Answer 2

Given

• Two circles are having the same centre.
• Radius of the larger circle = 10 cm
• Radius of the smaller circle = 4 cm

To find

• Area of the larger circle

Solution

Firstly, we will find the area of the smaller circle.

Using formula,

Area of circle = πr²

Where,

• Take π = 22/7
• r = radius of the circle

Substituting the given values,

⟶ 22/7 × 4 × 4

⟶ 50.28 cm²

❖ Area of the smaller circle = 50.28 cm²

Now, we will find the area of the larger circle including the smaller one.

Using formula,

Area of the circle = πr²

Substituting the given values,

⟶ 22/7 × 10 × 10

⟶ 314.28 cm²

❖ Area of the larger circle including the smaller one = 314.28 cm²

Now, to find the area of the larger circle.. subtract the area of the smaller circle from the area of the larger circle including the smaller circle.

❖ Area of the larger circle = Area of the larger circle including the smaller circle - Area of the smaller circle.

⟶ 314.28 - 50.28

⟶ 264 cm²

❖ Area of the larger circle = 264 cm²

Figure :-

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\qbezier(2.3,0)(2.121,2.121)(0,2.3)\qbezier(-2.3,0)(-2.121,2.121)(0,2.3)\qbezier(-2.3,0)(-2.121,-2.121)(0,-2.3)\qbezier(2.3,0)(2.121,-2.121)(-0,-2.3)\qbezier(1.2,0)(1.121,1.121)(0,1.2)\qbezier(1.2,0)(1.121,-1.121)(0,-1.2)\qbezier(0,-1.2)(-1.121,-1.121)(-1.2,0)\qbezier(-1.2,0)(-1.121,1.121)(0,1.2)\put(-0,0){\vector(-1,0){2.3}}\put(0,0){\vector(0,1){1.2}}\put(-1.9,0.2){ \bf 10~cm }\put(0.2,0.3){ \bf 4~cm }\end{picture}$