Question

the filament of a 240 V ,100W electric bulb heats up the room temperature .as it heats up its resistance increases by a factor of 16 what is the resistance of this bulb temperature

Answer 1

 Best Answer

... 
R at operating temp 
P = V^2 / R 
100 = 240^2 / R 
R = 576 ohm 
then take 1/16th of that 
576/16 = 36 ohm 

Answer 2

 

R at operating temp 

P = V^2 / R 

100 = 240^2 / R 

R = 576 ohm 

then take 1/16th of that 

576/16 = 36 ohm