Question

The filament of a bulb takes a current 100 mA when potential difference across it is 0.2V . When the potential difference across it becomes 400mA . Calculate the resistance of the filament in each case and account for the difference............. PLS DONT GIVE ABSURB ANSWERS ........" I HAVE ASKED THIS QUESTION FOUR TIMES NOW AND HAVEN'T GOT A SINHLE ANSWER RIGHT....AND THIS IS MY LAST TRY"

Answer 1

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✒ R1 = 2Ω & R2= 2.5Ω

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First case :-

• I1=0.1A

• V1 =0.2V

• R1 =?

⏩V1=I1 R1

⏩R1 = 0.2/0.1

➡ R1 =2Ω

Second Case :-

• I2 =0.2A

• V2=1V

• R2 =?

⏩V2 =I2 R2

⏩R2= 1/0.4

➡ R2 =2.5Ω

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Answer 2

Answer:

correct ANSWER ⬆️⬆️⬆️⬆️⬆️