The filament of a typical incandescent lightbulb is at a temperature of about 3,000K. For a 100-W lightbulb, what is the surface area (mm) of the filament?
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Answer:
P=eAσT4
Explanation:
An incandesent light bulb has a tungsten filament that is heated to a temperature
when an electric current passes through it If the surface area of the filament is approximately
and it has an emissivity of
the power radiated by the bulb is nearly <br>
(sigam=5.67×10−8Wm−2K−4)
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