Question

The filament of an electric lamp draws a current of 0.4A , which lights for 3 hours . What is the charge passing in this time interval?​

Answer 1

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Explanation:

➪The amount of charge flowing through the circuit is 4320 C

Given:

➪Current or I= 0.4 A

• Duration of the electric bulb lights = 3 hours

To find:

⟹ The amount of charge flowing through the circuit.

✯SOLUTION:✯

Charge is given by Q and is calculated by the formula:$\mathrm{Q}=I \times \mathrm{t}$

• Time has to calculated in seconds, so we get

$t= 3 \times 3600t=3×3600 = 10800 sec$

$\mathrm{Q}=0.4 \times 10800=4320 \mathrm{C}$

where,C is the Coulomb which is unit of charge.

Therefore, The amount of charge which flows through the circuit is found to be 4320 C