Question

the
find the range of value of
of x which satisfy
inequation 5 < 1 +
§ ; XER
+1​

Answer 1

Step-by-step explanation:

your answer

the range of value is

_. -1 XER

when using the inequtaton

that -1.0 XER

Answer 2

Step-by-step explanation:

The base of the logarithm is 1.5 which is greater than 1

So, in order for the inequation to be greater than 0

(

x−2

2x−8

) has to be greater than 1

∴

x−2

2x−8

>1⇒

x−2

2x−8

−1>0

⇒

x−2

2x−8−x+2

−1>0

⇒

x−2

x−6

>0

⇒(x>6,x>2) or (x<6,x<2)

Now, for the region refer to figure

So, x>2 and x<6

∴[2,6] region is avoided

∴x>6 or x<2.

Hence the solution is

(x>6 or x<2)

i.e., x∈(−∞,2)∪(6,∞)

solution