Question

the
Find two consecutive integers such that one.
fifth of the larger exceeds one-sixth of the
smaller by 3.​

Answer 1

Answer:

The integers are -> 84, 85

Step-by-step explanation:

let integer be x, x+1(because they are consecutive)

1/5(x+1) - 3 = 1/6 x

1/5x +1/5 - 3 = 1/6x

1/6x - 1/5x = 1/5 -3

(5x-6x)/30 = 1/5 - 15/5

-x/30 = -14/5

-5x = -14*30

-5x = -420

x = -420/-5

x = 84

x+1 = 85

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