Question

the first 16 term of the ap 1, 3, 5, 7, 9, is

Answer 1

Step-by-step explanation:

An= a+(n-1)d

a=1

n=16

d=2

16th term= 1+(16-1)2

= 1+15×2

= 1+30

= 31

Answer 2

Step-by-step explanation:

first term = 1 = a

second term = a+d = 3

1+d= 3

d=2

Common difference= 2

Now, nth term of an AP is a(n) = a+ (n-1)d

So, the 16th term will be a(16) = 1+(16-1)(2)

a(16)= 1+(15)(2)= 1+30=31

Hence, the sixteenth term will be 31.

Thank you