The first 3 terms of a sequence are 1/3,1/2,3/4...Identify the type of sequence and find sixth term
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the sequence is a Geometric Progression
the common difference r=(1/2)/(1/3)= 3/2
nth term, Aₙ=a×rⁿ⁻¹
sixth term, A₆=1/3 × (3/2)⁶⁻¹
= 1/3 × (3/2)⁵
= 1/3 × 243/32
=243/(32×3)
=81/32
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