Question

the first and last terms of an A.P are 2 and 98 respectively.if the sum of the series is 300.find the number of terms in the A.P and find the 11th term of the A.P

Answer 1

Step-by-step explanation:

i hope it helps you.....

Answer 2

Step-by-step explanation:

If the first term is 2 Then our a (the first term)

a = 2.

and last term l = 98.

and sum of the series Sl = 300.

With using the formula of Sl we will find the number of terms jn the AP

Sl = n/2 (a+l)

300 = n/2 (2+98)

300 = n/2×100

(300 × 2) /100 = n

6 = n.

So, the number of terms in the ap is 6.

Now , for finding the 11th term we will also need to find the d (common difference) of the AP series.

For that we know the last term , and by formlua of Tnth term, where.

Tn = a + (n-1)d

98 = 2 + (6-1) d

98 - 2 = 5d

5d = 96

d = 96 /5

Now for 11th term

T11 = a + (11 - 1) d

T11 = 2 + 10×96/5

T11 = 2 + 192

T11 = 194.

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