Question

The first and third term of then AP 30 and 26. find the 8 term​

Answer 1

Step-by-step explanation:

a1=30

a3=26

a3=a+2d=26

30+2d=26

2d=26- 30

2d= -4

d= -2

a8= a+7d

30+ 7×-2

=30-14

= 16

Answer 2

Step-by-step explanation:

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$\blue{First term= 30}$

$\blue{Third term=26 }$

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a = 30 ;

difference is :

→an = a + (n-1)d

→ a3 = a + (3 - 1) d

→26 = 30 + 2d

→26 - 30 = 2d

→ -4 = 2d

→d = -4/2

→d = -2

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Hence, d = -2, n = 8 and a = 30

Now let's find the 8th term,

→an = a + (n-1)d

→a8 = 30 + (8 - 1) -2

→ a8 = 30 + (-14)

→a8 = 30 - 14 = 16

Hence, a8 = 16

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$\huge\red{\mid{\fbox{{✯ a8 = 16}}\mid}}$

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