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Attempt question number 3rd.
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Given Principal = 4000, rate of interest = 5, Time = 2.5 years.
We know that A = P(1 + r/100)^n
= > 4000(1 + 5/100)^2
= > 4000(1 + 1/20)^2
= > 4000(21/20)^2
= > 4000(441/400)
= > 4410
Intrest after 2 years = 4100 - 4000
= 410
Interest after half year = (4410 * 5 * 1)/(100 * 2)
= 110.25
total interest after 2.5 years = 410 + 110.25
= 520.25
Hope this helps!
We know that A = P(1 + r/100)^n
= > 4000(1 + 5/100)^2
= > 4000(1 + 1/20)^2
= > 4000(21/20)^2
= > 4000(441/400)
= > 4410
Intrest after 2 years = 4100 - 4000
= 410
Interest after half year = (4410 * 5 * 1)/(100 * 2)
= 110.25
total interest after 2.5 years = 410 + 110.25
= 520.25
Hope this helps!
siddhartharao77:
:-)
answer is Rs 520.25
can you solve it correctly
tell me
i a solving.. i will solve..Dont worry...
I am
it's urgent
may i know why u reported my answer.. I cant edit now. Cant u wait for sometime. How do u think we can edit after reporting
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