Question

The first degree terms of ax? + 2hxy +by2 + 2gx+2fy +c= 0 are removed by shifting origin to (a,b). The new equation is 1) ax? + 2hxy + by2 + 2ya +2bB+c = 0 2) ax² + 2hxy +by2 + ga + f B+c=0 3) ax? + 2hxy +by2 +ha+bB+c=0 4) ax? + 2hxy - by? – ha - bß-c=0​

Answer 1

Answer:

r⋅r

1

⋅r

2

⋅r

3

=

s

△

×

s−a

△

×

s−b

△

×

s−c

△

⇒

s(s−a)(s−b)(s−c)

△

4

[r=

s

△

,r

1

=

s−a

△

,r

2

=

s−b

△

,r

3

=

s−c

△

]

r⋅r

1

⋅r

2

⋅r

3

=

△

2

△

4

=△

2

Hence, 2△ is the correct answer.

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