the first emission line in the atomic spectrum of hydrogen in the balmer series appears at
total number of spectral lines in UV region during transition from 5 th excited state to first excited state
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7
no. of spectral line=n2-n1
5th excited state......n=6 and 1st for excited state.... n=2
but for uv region n=1 so no electron is coming in ground state ie. n=1
so no. of spectral line =
answer =0
5th excited state......n=6 and 1st for excited state.... n=2
but for uv region n=1 so no electron is coming in ground state ie. n=1
so no. of spectral line =
answer =0
Answered by
3
Conditions given are:
a) Balmer series
b) 5th excited state to first excited state
c) UV region
Under UV region, the transition is from 5th excited state, i.e., n = 6, to first excited state, i.e., n = 2.
Balmer series refers to visible region. But here UV region is mentioned, hence no transition possible. Hence, the number of spectral lines for Balmer's series in UV region is zero.
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