Chemistry, asked by vains24, 6 hours ago

The first four ionisation enthalpies are Ga are 579, 1979,2963 and 6200 kj/ mol. how much energy is required to form each of the following ions Ga+, Ga2+, Ga3+ and Ga4+? why does the formation of Ga4+ require a comparatively large amount of energy? ​

Answers

Answered by egemy123
0

Answer yes

Explanation:

For breaking ions

Answered by dayaltk
0

Answer:

Explanation:

To calculate the energy needed to convert gallium atom to  by multiplying number of moles, of sodium, 0.1 with ionization enthalpy of gallium. That is,

The energy needed to convert gallium atom to  is 579x0.1

                                                                                     57.9x10^-3J

The energy needed to convert gallium atom to  is1979x0.2

                                                                                  595.8x10^-3J

The energy needed to convert gallium atom to 2963 x0.3

                                                                                  688.9x10^-3J  

The energy needed to convert gallium atom to  is 6200x0.4

                                                                                    2480x10^-3J

The required amount of energy of is higher than the energy among three gallium ions. Because, the outer electronic configuration of gallium is . And the outer electronic configuration of is.  

That means,  is a stable configuration. And it does not have any tendency to remove the outer electrons.  

Hence, a high amount of energy should be applied for the removal of outer electrons.  

Therefore, the required amount of energy of is higher than that of three gallium ions.

 

  • The required amount of energy of is higher than that of three gallium ions. Because, has a stable outer electronic configuration.
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