the first ionization potential of Na is 5.1ev . the value of electron gain enthalpy of Na+ will be
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Answered by
42
HEY USER...
Easy one ,
Na--------> Na⁺ + e⁻ ( first IE) ΔH = 5.1
Noe reaction is reversed :-
Na⁺ + e⁻ ----------> Na
so ΔH = -5.1eV
Thank you
HOPE IT HELPS..
Easy one ,
Na--------> Na⁺ + e⁻ ( first IE) ΔH = 5.1
Noe reaction is reversed :-
Na⁺ + e⁻ ----------> Na
so ΔH = -5.1eV
Thank you
HOPE IT HELPS..
Answered by
14
hi mate
hope it helps you...guy
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