Question

The first ionization potential of Na, Mg, Al and Si are in the
order
(a) Na < Mg > Al < Si (b) Na > Mg > Al > Si
(c) Na < Mg < Al > Si (d) Na > Mg > Al < Si

Answer 1

The first ionization potential of Na, Mg,Al,Si are in the order of

Na<Mg>Al<Si .

1) We know the following elements belong to the same period and in a period when we go from left to right size decreases.

Since Ionisation enthalpy is inversely proportional to size so Na being the biggest in size among these will have lowest first I.E and Si being the smallest will have highest first I.E.

2) We also know that I.E is directly proportional to penetrating power and it has following sequence s>p>d>f.

3) Since the last shell of Mg contain 3s2 and that of Al contain 3p1.

So penetrating power of Mg>Al so i

I.E of Mg>Al.

4) So the correct sequence is given in option (a).

Answer 2

Na < Mg > Al < Si is the trend of the 1st ionization potential of the atoms.

Explanation:

• Sodium is the element with atomic number 11 and electronic configuration  

• Na (11): [Ne] 3s1.

• Magnesium is the element with atomic number 12 and electronic configuration

• Mg (12): [Ne] 3s2.

• So magnesium has fulfilled 3s orbital.

• So it will have more ionization potential than the sodium.

• Aluminum is the element with atomic number 13 and electronic configuration

• Al: [Ne] 3s2 3p1.

• So, this being the element with p electron, has less ionization potential than magnesium.

• Silicon is the element with atomic number 14 and electronic configuration

• Si (14): [Ne] 3s2 3p2.

• So, silicon being more charged, has higher ionization potential than aluminium.

• So the trend of 1st ionization potential is Na < Mg > Al < Si.

For more information about ionization potential,

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If ionisation potential of H atom is 7.2x then energy difference between 2 amd 3 shell will be??

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If the ionisation potential is IP, electron affinity is EA and electronegativity is x then which of the following relation is correct :-

(A) 2X - EA - IP = 0

(B) 2EA - X - IP = 0

(C) 2IP - X - EA = 0

(D) All of the above​