The first-order reaction k = 4.6 s–1. If [A]o = 0.500 M, how long will it take to reach [A] = 0.125 M?
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Given :
The rate constant of the first order reaction = 4.6 /s
Initial concentration of reaction = 0.500 M
To find :
Time taken by the reaction to reduce the concentration of the reactant to 0.125 M .
Solution :
The Integral representation of the first order reaction is given by -
ln ( A / A ) = -kt
where , A is the concentration of the reactant at any time t ,
A is the initial concentration ,
k is rate constant ,
and t is time .
now ,
ln ( 0.125 / 0.500 ) = - ( 4.6 ) t
=> ln ( 1 / 4 ) = - ( 4.6 ) t
=> t = ( 1.386 ) / 4.6
=> t = 0.3 s {approx}
Time taken by the reaction to reduce the concentration of the reactant to 0.125 M is 0.3 seconds .
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