The first order reaction takes 40 minutes for 30 decomposition
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t = 2.303/k Log [R]º / [R]
k = 2.303/40min Log 100 / 100-30
= 2.303/40min Log 10 / 7
= 8.918 x 10-3 min-1
Therefore, t1/2 of the decomposition reaction is
t1/2 = 0.693/k
= 0.693 / 8.918 x 10-3 min
= 77.7 min (approximately
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Answer:
Explanation:
For a first order reaction,
t = 2.303/k Log [R]º / [R]
k = 2.303/40min Log 100 / 100-30
= 2.303/40min Log 10 / 7
= 8.918 x 10-3 min-1
Therefore, t1/2 of the decomposition reaction is
t1/2 = 0.693/k
= 0.693 / 8.918 x 10-3 min
= 77.7 min (approximately)
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