The first side of a triangle is 2 cm longer than the second side that third side is 5cm shorter than peace II side if the perimeter of the rectangle is 49 cm find the length of its side
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Let the 2 nd side be x.
Therefore 1st side = 2+x
Third Side= 2+x -5
Perimeter= 49
=>x+2+ x+2+x-5=49
=> 3x=48
=> x=16.
Therefore 1st side = 2+x
Third Side= 2+x -5
Perimeter= 49
=>x+2+ x+2+x-5=49
=> 3x=48
=> x=16.
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