the first tearm of an AP is 7, the last term is 47 and the sum is 432 find number of terms and common difference. please step by step
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Answer:
a=7 l=49 Sn=420
Sn=
2
n
[a+l]
So 420×2=n[7+49]
n=15
l=a+(n−1)d
⇒ 49=7+14 d
⇒ 7=1+2 d ⇒ 2d=6
⇒ d=3
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