The first term and the common difference of an A.P is 10,000 and 2000 respectively. Find the sum of first 12 terms of the A.P.
Answers
Answered by
19
a = 10000
d= 2000
term no 12 = 10000 + 11 * 2000
= 10000+ 22000 = 32000
sum of the first 12 terms = 12/2(10000+32000) = 6 * 42000 = 252000
hope it helps mark as brainliest plz :-)
d= 2000
term no 12 = 10000 + 11 * 2000
= 10000+ 22000 = 32000
sum of the first 12 terms = 12/2(10000+32000) = 6 * 42000 = 252000
hope it helps mark as brainliest plz :-)
ayan98542:
plz Mark as brainliest
Answered by
14
Answer:
a=10000
d=2000
n=12
then
Sn=n/2[2a+(n-1)d]
=12/2[20000+22000]
=6[42000]
=252000
Step-by-step explanation:
plzz mark as brainliest......
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