The first term and the last term of an AP are 17 and 350 respectively.if the common differencei is 9, how many terms are there and what are their sum
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First term of the A.P =17
Therefore a = 17
Last term of the A.P = 350
Therefore a + (n - 1)d = 350
Common difference of the A.P = 9
Therefore d = 9
Last term = 350
a + (n - 1)d = 350
17 + (n - 1)9 = 350
17 + 9n - 9 = 350
9n + 8 = 350
9n = 342
n = 38
Number of terms in the A.P = 38
Sum of the terms of the A.P = n/2 (a + l)
= 38/2 (17 + 350)
= 19 (367)
= 6973
The sum of the A.P = 6973
Hope this helps you
Therefore a = 17
Last term of the A.P = 350
Therefore a + (n - 1)d = 350
Common difference of the A.P = 9
Therefore d = 9
Last term = 350
a + (n - 1)d = 350
17 + (n - 1)9 = 350
17 + 9n - 9 = 350
9n + 8 = 350
9n = 342
n = 38
Number of terms in the A.P = 38
Sum of the terms of the A.P = n/2 (a + l)
= 38/2 (17 + 350)
= 19 (367)
= 6973
The sum of the A.P = 6973
Hope this helps you
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