the first term of an A.P. is 5,the last term is 45 and the sum of its term is 1000. Find the number of terms and the common difference of the A.P.
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Answered by
49
we have,
Sn=1000
a=5
l=45
We know that,
=> Sn=(n/2)(a+l)
[where 'n' is the number of terms]
Substitute all other values into the formula and find the value of n
=> 1000=(n/2)(5+45)
(1000/50)=n/2
20=n/2
n=20*2
n=40
Therefore the number of terms present is 40
Sn=1000
a=5
l=45
We know that,
=> Sn=(n/2)(a+l)
[where 'n' is the number of terms]
Substitute all other values into the formula and find the value of n
=> 1000=(n/2)(5+45)
(1000/50)=n/2
20=n/2
n=20*2
n=40
Therefore the number of terms present is 40
ajmalz444:
To find the common difference
An=a+(n-1)*d [where d is tgh
where d is the common differnce
lets take the last term => 45=5+39d=>40=39d=>d=(40/39)
Answered by
5
Answer:
n=40
Step-by-step explanation:
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