Math, asked by asdev2503, 1 year ago

the first term of an A.P. is 5,the last term is 45 and the sum of its term is 1000. Find the number of terms and the common difference of the A.P.

Answers

Answered by ajmalz444
49
we have,
Sn=1000
a=5
l=45

We know that,
=> Sn=(n/2)(a+l)
[where 'n' is the number of terms]

Substitute all other values into the formula and find the value of n
=> 1000=(n/2)(5+45)
     (1000/50)=n/2
      20=n/2
       n=20*2
       n=40

Therefore the number of terms present is 40

ajmalz444: To find the common difference
ajmalz444: An=a+(n-1)*d [where d is tgh
ajmalz444: where d is the common differnce
ajmalz444: lets take the last term => 45=5+39d=>40=39d=>d=(40/39)
Answered by kazabhargavaram
5

Answer:

n=40

Step-by-step explanation:

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