the first term of an ap is 14,the sum of first five terms of an ap are equal to the first ten terms in magnitude and opposite in sign
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First term =14
common diff=d
==> 5/2(2*14+(4)d)=-10/2(2*4+9d)
solve it
d=-42/11
t3=a+ 2d=70/11
common diff=d
==> 5/2(2*14+(4)d)=-10/2(2*4+9d)
solve it
d=-42/11
t3=a+ 2d=70/11
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