the first term of an AP is 2 and 9th term is 26, find the common difference
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Answered by
2
Explanation:
Let a is first term and d is common difference of an A.P.
t1=a=2
tn=a+(n-1)d
t9=a+(9-1)d
26=2+8d
8d=26-2
8d=24
d=24/8
d=3
Therefore,the common difference is 3.
Answered by
0
Explanation:
Let a is first term and d is common difference of an A.P.
t1=a=2
tn=a+(n-1)d
t9=a+(9-1)d
26=2+8d
8d=26-2
8d=24
d=24/8
d=3
Therefore,the common difference is 3.
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