Question

please solve the question.
The volume of water that must be added to a mixture of 250ml of 0.6M HCL [Hydrochloric acid]to obtain 0.2M of HCL.​

Answer 1

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$\boxed{200ml}$

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We can see that the number of moles of HCL should remain constant as per the law of conservation of mass.

Since we have the molarity,we can calculate the number of moles using,

Number of moles=Molarity×volume of solution

Initial number of moles=250×0.6+0.2×750

Final number of moles=0.25(250+750+ $\displaystyle {V_ required}$)

Equating,we get $\displaystyle { V_ required }$=$\frac{0.6×250+0.2×750}{0.25}-[1000] = \boxed{200ml}$