Question

the first term of an ap is 2 and the last term is 58 find the C.D if the sum of all the term is 60 ​

Answer 1

Answer:

the common difference is 56.

Answer 2

The common difference between the terms will be "d=56". Further explanation is given below.

Step-by-step explanation:

According to the question,

Given:

The first term, a, T₁=2

The last term, l, T₂=58

Sum of the terms, Sn=60

Now,

Sum of the term, Sn=$\frac{n}{2}$[T₁+T₂]

On putting the values of T₁, T₂, and Sn in the above formula, we get

                            60=$\frac{n}{2}$[2+58]  

                            60=$\frac{n}{2}$[60]

                        60×2=n×60  

                           120=n×60  

                             $\frac{120}{60}$=n

                              n=2

To find the common difference (d) between the terms, put the given values in the formula given below,

                            Tn=a+(n-1)d

On putting the values of Tn, a, and n, we get

                            58=2+(2-1)d

                            58=2+d

                              d=58-2

                              d=56 (Common difference)

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